Andor Season 2’s Final Episodes Will Lead Into Star Wars: Rogue One

0
120

Maggie Dela Paz

Curated From www.comingsoon.net Check Them Out For More Content.

In a recent interview with Empire Magazine, Tony Gilroy revealed a new detail about the upcoming second season of Lucasfilm’s Disney Plus series Andor, currently in production in the UK. Gilroy confirmed that the last three episodes of the 12-episode final installment are expected to cover the last three days before the events of 2016’s Rogue One: A Star Wars Story.

Lead star Diego Luna also teased the different risks they’ll take in Andor’s sequel season. “Look, man, I’m not trying to make a career here; if anything I’m on the downhill side of a long career,” Gilroy added. “But this is an opportunity. This is 1,500 pages of the most dynamic material in these people’s lives to deal with. We got it right the first time, and you don’t want to let your foot off the gas.”

What to Expect in Andor Season 2?

Disney Plus’s Andor features Diego Luna reprising his role as Cassian Andor. Set five years before the events of Rogue One, the series follows the adventures of the titular hero rebel spy during the formative years of the Rebellion. Set to premiere in August 2024, the season is expected feature time jumps involving Andor’s missions for the Rebel Alliance.

Franchise alums Forest Whitaker as Saw Gerrera, Genevieve O’Reilly as Mon Mothma, and Alan Tudyk as Cassian’s droid sidekick K-2SO are also returning for Season 2 along with Denise Gough, Stellan Skarsgård, Kyle Soller, and Adria Arjona.

Andor is executive produced by showrunner and creator Gilroy, who previously directed the reshoots for Rogue One. Gilroy was originally expected to direct three episodes but was forced to give up the position to Black Mirror‘s Toby Haynes due to pandemic-related travel issues.

The 2016 film was a critical and box-office hit with a gross of over $1 billion worldwide. It starred Luna, Felicity Jones, Mads Mikkelsen, Donnie Yen, Jiang Wen, Riz Ahmed, Forest Whitaker, and Ben Mendelsohn.

Source link

Advertisement